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**Aliquantus** I have the following function: $\displaystyle f(x,y)=x^4+2x^3y+x^2y^2+y^4$ and I know that there is a critical point at $\displaystyle (0,0)$. I have been asked to determined the type of critical point. The second derivatives give no information, and I'm not supposed to consider higher derivatives.

"Obviously" it is a minimum point, so I thought it would be enough to show that $\displaystyle f(x,y)\geq 0$ near $\displaystyle (0,0)$.

By introducing polar coordinates I got:

$\displaystyle f(r\cos(\theta),r\sin(\theta))=...=r^4\left[1+2\cos^3(\theta)\sin(\theta)-cos^2(\theta)\sin^2(\theta)\right]$.

Since $\displaystyle r^4\geq 0$, it should be enough to show that $\displaystyle 1+2\cos^3(\theta)\sin(\theta)-cos^2(\theta)\sin^2(\theta)\geq 0$, but I seem unable to do it. Does this seem like the right method, and if so, does anyone know how to go on from here?

Another thought I had was to compare with $\displaystyle (x+y)^4$ or $\displaystyle (x-y)^4$, but that didn't get me anywhere.

Aliquantus