Results 1 to 4 of 4

Math Help - Limit question (please help)

  1. #1
    Newbie
    Joined
    Apr 2010
    Posts
    18

    Limit question (please help)

    lim as x goes to 0 from the positive direction of sqrt(x)log(x)

    correct me if I'm wrong but the actual limit at x=o does not exist yes?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member Random Variable's Avatar
    Joined
    May 2009
    Posts
    959
    Thanks
    3
     \lim_{x \to 0^{+}} \sqrt{x} \ln x = \lim_{x \to 0+} \frac{\ln x}{\frac{1}{\sqrt{x}}} = \lim_{x \to 0^{+}} \frac{\frac{1}{x}}{\frac{-1}{2x^{\frac{3}{2}}}} = \lim_{x \to 0^{+}} -2 \sqrt{x} = 0
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Apr 2010
    Posts
    18
    Thanks a heap, but does the limit at x=0 exist?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor

    Joined
    Apr 2005
    Posts
    15,372
    Thanks
    1314
    Does 0 exist?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 4
    Last Post: November 7th 2011, 03:27 PM
  2. Replies: 1
    Last Post: August 8th 2010, 11:29 AM
  3. Limit question
    Posted in the Calculus Forum
    Replies: 5
    Last Post: May 1st 2010, 08:30 PM
  4. Limit question of course!
    Posted in the Calculus Forum
    Replies: 5
    Last Post: April 19th 2008, 09:06 PM
  5. Limit question
    Posted in the Calculus Forum
    Replies: 2
    Last Post: November 4th 2006, 12:47 AM

Search Tags


/mathhelpforum @mathhelpforum