Hey all,

I have done this question but don't seem to get the same answer as given, i don't know where I am going wrong? can someone check for me please. Thank you

Find dy/dx using the product rule when: y=x^2lnxcos3x

u=x^2

du/dx=2x

v=lnxcos3x

a=lnx, b=cos3x

dv/dx=a.db/dx+b.da/dx

da/dx=1/x

db/dx=-3sin3x

dv/dx=lnx.-3sin3x+cos3x.1/x

dv/dx=-3lnxsin3x+cos3x/x

dy/dx=u.dv/dx+v.du/dx

dy/dx=x^2.-3lnxsin3x+cos3x/x+lnxcos3x.2x

dy/dx=-3x^2lnxsin3x+co3x/x+2xlnxcos3x