# volume, triple integral

• April 17th 2010, 08:06 PM
jmedsy
volume, triple integral
Graph the first octant portion of the surface

$z=9-x^2,2 \leq y \leq 5;$

Find the volume of the solid over the xy-plane and under the surface.

Is this the correct answer?

$\int_0^3 \int_2^5 \int_0^{9-x^2} 1 \, dz \, \, dy \, dx$
• April 17th 2010, 09:09 PM
dwsmith
Quote:

Originally Posted by jmedsy
Graph the first octant portion of the surface

$z=9-x^2,2 \leq y \leq 5;$

Find the volume of the solid over the xy-plane and under the surface.

Is this the correct answer?

$\int_0^3 \int_2^5 \int_0^{9-x^2} 1 \, dz \, \, dy \, dx$

Looks ok to me.