Originally Posted by

**ramdrop** I assume you move it over the the other side, so you have

0 (lessthan equal to) x - 1 - ln(x): If i differentiate that, I get 1 - 1/x.

If i was to move that back say, 1/x (lessthan equal to) 1. Multiply through by x, to get 1 on the left, and x on the right.

So: 1 (lessthan equal to) x - for all x>0..

Or am i going completely wrong?

Here I would just work out the integral of the function $\displaystyle \frac{1}{1+ x^2}$ . I think I could do thatm but again, unsure where to go after..