looks like this: f(x) = x/(9+x^2) need to find the interval of convergence. thanks for any help.
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Originally Posted by rcmango looks like this: f(x) = x/(9+x^2) need to find the interval of convergence. thanks for any help. f(x) = x/(9+x^2) = x/9 [1+(x/3)^2] and the usual series expansion of 1/(1+(x/3)^2) is derived from that of 1/(1+z), with z=(x/3)^2, which is convergent for |z|<1, so is convergent for |x|<3. RonL
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