Find the general solution of the given differential equation. y'' + 5y' = 0 The answer is y = C1 + C2*e^(-5t) I don't know where to begin with this, unfortunately I missed this lecture. Thanks.
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Originally Posted by pakman Find the general solution of the given differential equation. y'' + 5y' = 0 The answer is y = C1 + C2*e^(-5t) I don't know where to begin with this, unfortunately I missed this lecture. Thanks. The characheeristic equation: k^2+5k=0 k(k+5)=0 k=0 or k=-5 Thus, e^0 = 1 and e^{-5t} are solutions. All linear combinators are, C_1(1)+C_2*e^{-5t}
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