how does the first underlined part become the second.. does the.. x e^x-1 cancel? where does the -2 come from? Help. Thankss
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Nothing cancels, it's from filling in the boundaries. $\displaystyle \left[-(x^2+1)e^{-x}\right]^{1}_{0}=\left(-(1^2+1)e^{-1}\right)-\left(-(0^2+1)e^{0}\right) = -2e^{-1}+1$
Originally Posted by calculus0 how does the first underlined part become the second.. does the.. x e^x-1 cancel? where does the -2 come from? Help. Thankss Dear calculus0, $\displaystyle \left[-(x^{2}+1)e^{-x}\right]_{0}^{1}=\left[-(1^{2}+1)e^{-1}\right]-\left[-(0^{2}+1)e^{-0}\right]=-2e^{-1}+1$ Hope this will help you.
thank you both.
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