can some make sense of this, where does the 5/4 I come from? i know you have to do some shifting because the last integral is "e^(-theta)cos2(theta)d(theta)" which is the same as the intial one.

thanks

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- April 15th 2010, 11:55 PMcalculus0integration by parts
can some make sense of this, where does the 5/4 I come from? i know you have to do some shifting because the last integral is "e^(-theta)cos2(theta)d(theta)" which is the same as the intial one.

thanks - April 16th 2010, 12:03 AMbrouwer
Yes, your initial integral is called I. By using integration by parts the same integral came back in the righthandside of the equation. So you can now solve the equation for I, your initial integral. That's basically all.

- April 16th 2010, 12:16 AMcalculus0
oh.. so I move 1/4 over to the left side and solve for I?? i get it. thank u!