Results 1 to 3 of 3

Math Help - Power series calculus 2?

  1. #1
    Newbie
    Joined
    Nov 2009
    Posts
    14

    Power series calculus 2?

    given that a power series for 1/(1-x) is sum.n=0,inf. x^n

    what is the power series for 1/(1-x)^2

    thanks
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member Failure's Avatar
    Joined
    Jul 2009
    From
    Zürich
    Posts
    555
    Quote Originally Posted by andrewt328 View Post
    given that a power series for 1/(1-x) is sum.n=0,inf. x^n

    what is the power series for 1/(1-x)^2

    thanks
    For example, by use of the "derivation trick", you get
    \frac{1}{(1-x)^2}=\frac{d}{dx}\frac{1}{1-x}=\frac{d}{dx}\sum_{n=0}^\infty x^n=\sum_{n=0}^\infty\frac{d}{dx}x^n=\sum_{n=1}^\i  nfty n x^{n-1}=\sum_{n=0}^\infty (n+1)x^n
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Nov 2009
    Posts
    14
    thank you!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 3
    Last Post: September 29th 2010, 06:11 AM
  2. Replies: 1
    Last Post: May 3rd 2008, 09:51 AM
  3. Replies: 10
    Last Post: April 18th 2008, 10:35 PM
  4. Calculus Power Series
    Posted in the Calculus Forum
    Replies: 1
    Last Post: March 10th 2008, 05:34 PM
  5. Calculus: Multiplying two power series
    Posted in the Calculus Forum
    Replies: 2
    Last Post: April 5th 2007, 09:13 AM

Search Tags


/mathhelpforum @mathhelpforum