Evaluate Indefinite integral as an infinite series
Last edited by mr fantastic; Apr 16th 2010 at 04:49 AM. Reason: Restored deleted question
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Originally Posted by racewithferrari Evaluate Indefinite integral as an infinite series $\displaystyle \int\frac{e^x-1}{x}\,dx = \int\frac{\sum_{k=0}^\infty\frac{x^k}{k!}-1}{x}\,dx=\int\sum_{k=1}^\infty\frac{x^{k-1}}{k!}\,dx= \sum_{k=1}^\infty\int \frac{x^{k-1}}{k!}=\sum_{k=1}^\infty \frac{x^k}{k\cdot k!}+C$
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