Whats the derivative of( x^2(sin^2)cos(3x))/sqrt56
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Originally Posted by wolfhound Whats the derivative of( x^2(sin^2)cos(3x))/sqrt56 Product rule and chain rule $\displaystyle u = x^2 \: \rightarrow \: u' = 2x$ $\displaystyle v = \sin^2 (\cos(3x)) \: \rightarrow \: v' = -6\sin(\cos(3x)) \sin(3x)$ $\displaystyle \frac{1}{\sqrt{56}} \left(2x \sin^2 (\cos 3x) - 6x^2\sin(\cos(3x)) \sin(3x)\right)$
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