If the line is parallel to the vector v = < -2,1,3>, what is the equation of the plane containing L and the point B = (-2,3,1)

A) - x + y + z = 6

B) 3x - 2y - z = 4

C) x + 6y -11z = 5

D) x + 5y - z = 12

E) 2x + 10y - 19z = 7

I know we can get the equation of the line because we have a point on the line and a vector parallel

So x = xo + at, y = yo + bt , z = zo + ct

x = -2 + -2t

y = 3 + t

z = 1 + 3t

I know the equation of a plane is a(x - xo) + b(y - yo) + c(z - zo) = 0. But the vector here <a,b,c> has to be normal to the plane...