OK so i started by setting them equal to each other. then I solved for x.
I got (+,- 5/9,6.25) then I subtracted y upper from y lower.
I am trying to do the problem, but I just cant get it.
Can anyone help?
Thanks.
Sketch the region enclosed by and . Decide whether to integrate with respect to or . Then find the area of the region.
I am not looking for the answer, just the name of the topic. I have no idea where to start and was hoping I could use the book to find out how to approach this problem. Thanks. The hw is due in an hour, and i still have 2 more problems to go!
Here is the graph. it is easier to integrate with respect to x. to find the limits of the integration, solve 4x^2 = 5x. obviously one limit will be zero, find the other one. then integrate 5x - 4x^2 since 5x is the higher function
i'm off to bed, you're on your own
for the limits of integration:
5x = 4x^2
=> 4x^2 - 5x = 0
=> x(4x - 5) = 0
=> x = 0 or 4x - 5 = 0
so x = 0 and x = 5/4
so the limits of integration are 0 up to 5/4
the area is given by:
int{0:5/4}(5x - 4x^2)dx
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if there is anything you're unsure about, ask now, i'll be in bed in about a minute, i'm already falling asleep while sitting here
what is the other question by the way?