Find the equation of the line that is tangent to at Shown work would be appreciated, thank you.
Last edited by Eixo; April 13th 2010 at 04:44 PM.
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Originally Posted by Eixo Find the equation of the line that is tangent to y = x^2sin(2x) at x = pi. Shown work would be appreciated, thank you. why don't you show the work of finding , first?
Originally Posted by skeeter why don't you show the work of finding , first? That's unfortunately where I've run into my trouble. I know how to do the rest of the question, however I am unsure on how to find
Originally Posted by Eixo That's unfortunately where I've run into my trouble. I know how to do the rest of the question, however I am unsure on how to find product rule + chain rule for ... where and this is a very basic process. give it a go ...
Thank you for the help, it was the mental roadblock that I was struggling to get past. I then subbed in (typo from original post, will edit). @ Slope = Slope (Cross multiply)
Last edited by Eixo; April 13th 2010 at 04:50 PM.
Originally Posted by Eixo Thank you for the help, it was the mental roadblock that I was struggling to get past. =(x^2)(2cos(2x))+(2x)(2sin(2x)) close ... now sub in for x to find the slope. use of the point-slope form is a bit easier ... ...
Sorry, will correct. My answer remains unchanged though.
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