Hey all, I'm a little new here and am having trouble toward the end of the semester with my calculus assignments and appreciate all the help I can get.
Find the critical values for the function.
f(x)= 20x^3 – 3x^5
To solve this you need to compute the derivative of and set it equal to 0.
See section 3 for a quick fix.
Derivative - Wikipedia, the free encyclopedia
So for your function we get...
Clearly x=0 is a solution but we also have...
(Divide through by 15)...
Divide through by ...
which is the same as solving...
=>
Hence
So 3 solutions are x=0, x=-2 and x=2.