Hey all, I'm a little new here and am having trouble toward the end of the semester with my calculus assignments and appreciate all the help I can get.

Find the critical values for the function.

f(x)= 20x^3 – 3x^5

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- April 13th 2010, 06:24 AMakuczma86Critical Value Problem
Hey all, I'm a little new here and am having trouble toward the end of the semester with my calculus assignments and appreciate all the help I can get.

Find the critical values for the function.

f(x)= 20x^3 – 3x^5 - April 13th 2010, 06:46 AMDeadstar
To solve this you need to compute the derivative of and set it equal to 0.

See section 3 for a quick fix.

Derivative - Wikipedia, the free encyclopedia

So for your function we get...

Clearly x=0 is a solution but we also have...

(Divide through by 15)...

Divide through by ...

which is the same as solving...

=>

Hence

So 3 solutions are x=0, x=-2 and x=2.