That answer is correct for the integral given.
I would like to know if my thinking on the problem is correct. I need to find the area between the circles and
After I graphed the 2 circles I looked at them and realized that the area between them is symmetric so I only need to find one half of it and multiply it by 2. So I figured that if I just took the circle and did the integral I would get the area bounded between the two circles. In the end I got
Could someone tell me if I am correct. Thank you.
I believe so. I know I answered this question a month or so ago but I can't remember what the outcome was.
Integrating the sin function from 0 to pi/4 is the right idea.
The answer is reasonable too so I think you have it.
The thread I did whenever is at physicsforums.com.
The answer is right.
Double integrals of polar equations help! - Page 2