On the closed interval [0,2pi], the maximum value of the function f(x)=4sinx-3cosx is: A.)3 B.)4 C.)24/5 D.)5 E.)None of these Explanations appreciated.
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Originally Posted by Manabu On the closed interval [0,2pi], the maximum value of the function f(x)=4sinx-3cosx is: A.)3 B.)4 C.)24/5 D.)5 E.)None of these Explanations appreciated. for max let Can you finish this?
Originally Posted by Manabu On the closed interval [0,2pi], the maximum value of the function f(x)=4sinx-3cosx is: A.)3 B.)4 C.)24/5 D.)5 E.)None of these Explanations appreciated. A couple of suggestions: Have you learnt to write that function in the form sin (a+b) or cos(a+b)? If so, that'd be the easiest way. 2. Calculus??
Originally Posted by pickslides for max let Can you finish this? Not really. I understand how you got to that point, but I'm not 100% sure how to calculate maximum values.
Originally Posted by Manabu On the closed interval [0,2pi], the maximum value of the function f(x)=4sinx-3cosx is: A.)3 B.)4 C.)24/5 D.)5 E.)None of these Explanations appreciated. D. is the correct answer, and it can be found without calculus (but with some trigonometry), because for . Now, since x varies over a whole period of the function, the maximum value of f(x) must be 5.
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