I am having trouble with the problem: lim (y+2) -2/(y-2) y->2
Follow Math Help Forum on Facebook and Google+
Originally Posted by sydewayzlocc I am having trouble with the problem: lim (y+2) -2/(y-2) y->2 Is everything under the squareroot?
no, sorry for the confusion, it is only the quantity (y+2) under the square root
$\displaystyle \lim_{y\rightarrow2}\sqrt{y+2}-\lim_{y\rightarrow2}\frac{2}{y-2}$ Solving these separately may be easier.
can you elaborate on that a little?
Originally Posted by sydewayzlocc can you elaborate on that a little? What is the limit of the first one?
isnt it 2?
Correct. $\displaystyle 2-\lim_{y\rightarrow2}\frac{2}{y-2}$ What is the limit of the last limit now?
Last edited by dwsmith; Apr 12th 2010 at 08:37 PM.
it produces the indeterminate form 0/0.
Try evaluating the limit from the left and right.
Last edited by dwsmith; Apr 12th 2010 at 08:21 PM. Reason: Used the wrong word
can you help with lim e^(2x)-1/e^(x)-1 x->0
Did you ever solve the first one?
yes i got 1/4 as the limit
Originally Posted by sydewayzlocc yes i got 1/4 as the limit That second limit doesn't exist.
Originally Posted by sydewayzlocc can you help with lim e^(2x)-1/e^(x)-1 x->0 Use L'Hopital's Rule
View Tag Cloud