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Math Help - help with limits please?

  1. #1
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    help with limits please?

    I am having trouble with the problem:

    lim (y+2) -2/(y-2)
    y->2
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  2. #2
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    Quote Originally Posted by sydewayzlocc View Post
    I am having trouble with the problem:

    lim (y+2) -2/(y-2)
    y->2

    Is everything under the squareroot?
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  3. #3
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    no, sorry for the confusion, it is only the quantity (y+2) under the square root
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  4. #4
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    \lim_{y\rightarrow2}\sqrt{y+2}-\lim_{y\rightarrow2}\frac{2}{y-2}

    Solving these separately may be easier.
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  5. #5
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    can you elaborate on that a little?
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  6. #6
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    Quote Originally Posted by sydewayzlocc View Post
    can you elaborate on that a little?
    What is the limit of the first one?
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  7. #7
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    isnt it 2?
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  8. #8
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    Correct.

    2-\lim_{y\rightarrow2}\frac{2}{y-2}

    What is the limit of the last limit now?
    Last edited by dwsmith; April 12th 2010 at 08:37 PM.
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  9. #9
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    it produces the indeterminate form 0/0.
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  10. #10
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    Try evaluating the limit from the left and right.
    Last edited by dwsmith; April 12th 2010 at 08:21 PM. Reason: Used the wrong word
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  11. #11
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    can you help with

    lim e^(2x)-1/e^(x)-1
    x->0
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  12. #12
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    Did you ever solve the first one?
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  13. #13
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    yes i got 1/4 as the limit
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  14. #14
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    Quote Originally Posted by sydewayzlocc View Post
    yes i got 1/4 as the limit
    That second limit doesn't exist.
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  15. #15
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    Quote Originally Posted by sydewayzlocc View Post
    can you help with

    lim e^(2x)-1/e^(x)-1
    x->0
    Use L'Hopital's Rule
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