What does ln2 equal? I'm stuck at that. Is there a formula for the derivative of ln(2^x)?
The problem is:
Use logarithmic differentiation to differentiate the following functions:
f(x)=2^x.
I got: ln(f(x))=ln(2^x)
d/dx [lnf(x)]=[f'(x)]/[f(x)=[x(2^(x-1)]/(2^x)
f'(x)=f(x)[x(2^(x-1)]/(2^x)=[x2^(x-1)]
But the answer says it's (2^x)ln2