Integration

**mag6** · April 12th 2010, 02:06 AM

need help with this.....

**mr fantastic** · April 12th 2010, 02:08 AM

Originally Posted by mag6

need help with this.....

Substitute $u = 1 + \ln x$ .

**mag6** · April 12th 2010, 02:10 AM

Originally Posted by mr fantastic

Substitute $u = 1 + \ln x$ .

yea....i did tht but i am having problem with plugging in e^6.....

**mr fantastic** · April 12th 2010, 02:19 AM

Originally Posted by mag6

yea....i did tht but i am having problem with plugging in e^6.....

$x = e^6 \Rightarrow u = 1 + \ln e^6 = 1 + 6 \ln e = 1 + 6 = 7$ .

Thread: Integration