1. ## Integration

need help with this.....

2. Originally Posted by mag6

need help with this.....
Substitute $u = 1 + \ln x$.

3. Originally Posted by mr fantastic
Substitute $u = 1 + \ln x$.
yea....i did tht but i am having problem with plugging in e^6.....

4. Originally Posted by mag6
yea....i did tht but i am having problem with plugging in e^6.....
$x = e^6 \Rightarrow u = 1 + \ln e^6 = 1 + 6 \ln e = 1 + 6 = 7$.