need help with this.....
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Originally Posted by mag6 need help with this..... Substitute $\displaystyle u = 1 + \ln x$.
Originally Posted by mr fantastic Substitute $\displaystyle u = 1 + \ln x$. yea....i did tht but i am having problem with plugging in e^6.....
Originally Posted by mag6 yea....i did tht but i am having problem with plugging in e^6..... $\displaystyle x = e^6 \Rightarrow u = 1 + \ln e^6 = 1 + 6 \ln e = 1 + 6 = 7$.
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