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Math Help - Displacement (net change)

  1. #1
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    Displacement (net change)

    The velocity function is v(t)= -t^2 +4t -3 for a particle moving along a line. Find the displacement (net distance covered) of the particle during the time interval [-1,6].

    I've tried integrating the function and then plugging in the values.
    Also I tried factorizing the function and dividing the integral based on the negative and positive sign and then integrating and plugging the values.

    But none of the methods give the right answer. Anybody got other ideas?
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  2. #2
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    Don't leave us hanging man! What is the right answer?
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    Quote Originally Posted by maddas View Post
    Don't leave us hanging man! What is the right answer?
    I have no idea!!!! I gotta solve this question for an assignment that I have to submit tomorrow and I'm really stuck!
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  4. #4
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    Quote Originally Posted by mag6 View Post
    The velocity function is v(t)= -t^2 +4t -3 for a particle moving along a line. Find the displacement (net distance covered) of the particle during the time interval [-1,6].

    I've tried integrating the function and then plugging in the values.
    Also I tried factorizing the function and dividing the integral based on the negative and positive sign and then integrating and plugging the values.

    But none of the methods give the right answer. Anybody got other ideas?
    Have you tried integrating the velocity to find displacement as a function of time without bounds.
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  5. #5
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    If you don't know the right answer, how do you know that the integral of v from -1 to 6 is wrong?
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    Quote Originally Posted by AllanCuz View Post
    Have you tried integrating the velocity to find displacement as a function of time. Then plug in d(6) + d(-1)?
    yea....I did that....the answer ws 70/3 or something. But that's not working
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    Quote Originally Posted by maddas View Post
    If you don't know the right answer, how do you know that the integral of v from -1 to 6 is wrong?
    Its an online assignment. So when you submit an answer it tells you immediately if its rite or wrong....
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  8. #8
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    Quote Originally Posted by mag6 View Post
    yea....I did that....the answer ws 70/3 or something. But that's not working
    Yes I know. I'm slightly tired right now lol.

    What does the integral of the velocity equation represent?
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    Quote Originally Posted by AllanCuz View Post
    Yes I know. I'm slightly tired right now lol.

    What does the integral of the velocity equation represent?
    the v(t) is the velocity at time t and the integral would be the net distance covered by the particle in time t.....i guess!
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  10. #10
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    +70/3 or -70/3?
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    Quote Originally Posted by maddas View Post
    +70/3 or -70/3?
    oh man.....thanks so much.....i had tried 70/3 but hadn't tried -70/3.....its working!
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  12. #12
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    Oh sign errors, you all-too-familiar seductress you!
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  13. #13
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    Quote Originally Posted by maddas View Post
    Oh sign errors, you all-too-familiar seductress you!
    oh yea.....thats me.....lol

    anyways here's another one if anyone's up for it.....I'm at a total loss here.

    Two people, Jaime and Tyler, are racing each other. Assume that both their accelerations are constant, Jaime covers the last 1/10 of the race in 7 seconds, and Tyler covers the last 1/7 of the race in 10 seconds. Who wins, and by how much?
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