Originally Posted by

**AllanCuz** See that's kind of important. I didn't know you already subbed in for time! lol

Um...not entirely

Look at your denominator. Where is this min? Well it is min when t=0, why? because the part

$\displaystyle 1 + 9e^-kt = 1 + 9/(e^{kt})$

Which you can see only gets smaller as time increases. And this is the denominator of our fraction. So smaller denominator --> bigger number

So lets take this to the limit. What happens to our function as t approaches infinity? Well our equation goes to 100. So we have an aysmtote at 100, not at 0.

When t=0 the interscept is 10, not 100.