# Thread: [SOLVED] squeeze theorem for sequences

1. ## [SOLVED] squeeze theorem for sequences

I don't understand how to use the squeeze theorem at all. The problem is:

Use the squeeze theorem to determine what an=(ncosn)/(n^2) converges to?

2. Originally Posted by Amberosia32
I don't understand how to use the squeeze theorem at all. The problem is:

Use the squeeze theorem to determine what an=(ncosn)/(n^2) converges to?
$a_n = \frac{n \cos n}{n^2} = \frac{\cos n}{n}$

Since $-1 \le \cos n \le 1$ then $\frac{-1}{n} \le \frac{\cos n}{n} \le \frac{1}{n}$. Now take limits.

3. Originally Posted by Danny
$a_n = \frac{n \cos n}{n^2} = \frac{\cos n}{n}$

Since $-1 \le \cos n \le 1$ then $\frac{-1}{n} \le \frac{\cos n}{n} \le \frac{1}{n}$. Now take limits.
Thank you. I thought it would be much more complicated.