Thread: Differential calculus

Pleas help:

Find the equation of the tangent to the graph 12=x^3 +xy + 3y^2 at the point (0,2).Determine where the tangent cuts the curve again.

Thanks

Originally Posted by mamamia

Find the equation of the tangent to the graph 12=x^3 +xy + 3y^2 at the point (0,2).Determine where the tangent cuts the curve again.

implicit derivative ... what did you get for ?