# Differential calculus

• April 10th 2010, 08:05 PM
mamamia
Differential calculus
Pleas help:

Find the equation of the tangent to the graph 12=x^3 +xy + 3y^2 at the point (0,2).Determine where the tangent cuts the curve again.

Thanks :)
• April 10th 2010, 08:09 PM
skeeter
Quote:

Originally Posted by mamamia
Find the equation of the tangent to the graph 12=x^3 +xy + 3y^2 at the point (0,2).Determine where the tangent cuts the curve again.

implicit derivative ... what did you get for $\frac{dy}{dx}$ ?