Pleas help:

Find the equation of the tangent to the graph 12=x^3 +xy + 3y^2 at the point (0,2).Determine where the tangent cuts the curve again.

Thanks :)

Printable View

- April 10th 2010, 08:05 PMmamamiaDifferential calculus
Pleas help:

Find the equation of the tangent to the graph 12=x^3 +xy + 3y^2 at the point (0,2).Determine where the tangent cuts the curve again.

Thanks :) - April 10th 2010, 08:09 PMskeeter