find area enclosed by curve y= x^2 -3x + 4 , and the xaxis how do I do this? is it just an indefinite integral so area is x^3/(3) -(3/2)x^2 +4x + C??
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Originally Posted by BadMonkey find area enclosed by curve y= x^2 -3x + 4 , and the xaxis how do I do this? is it just an indefinite integral so area is x^3/(3) -(3/2)x^2 +4x + C?? no, it will be definite integral ... roots of the equation will be your limits of integration. remember to compensate for the fact that a definite integral yields "signed" area.
Oh thanks I see, yes I will remember the areas add(cannot have negative area) thank you
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