Thread: area enclosed by curve

find area enclosed by curve y= x^2 -3x + 4 , and the xaxis

how do I do this? is it just an indefinite integral
so area is x^3/(3) -(3/2)x^2 +4x + C??

Originally Posted by BadMonkey

find area enclosed by curve y= x^2 -3x + 4 , and the xaxis

how do I do this? is it just an indefinite integral
so area is x^3/(3) -(3/2)x^2 +4x + C??

no, it will be definite integral ... roots of the equation will be your limits of integration.

remember to compensate for the fact that a definite integral yields "signed" area.

Oh thanks I see,
yes I will remember the areas add(cannot have negative area)
thank you