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Math Help - area enclosed by curve

  1. #1
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    area enclosed by curve

    find area enclosed by curve y= x^2 -3x + 4 , and the xaxis

    how do I do this? is it just an indefinite integral
    so area is x^3/(3) -(3/2)x^2 +4x + C??
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  2. #2
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    Quote Originally Posted by BadMonkey View Post
    find area enclosed by curve y= x^2 -3x + 4 , and the xaxis

    how do I do this? is it just an indefinite integral
    so area is x^3/(3) -(3/2)x^2 +4x + C??
    no, it will be definite integral ... roots of the equation will be your limits of integration.

    remember to compensate for the fact that a definite integral yields "signed" area.
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  3. #3
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    Oh thanks I see,
    yes I will remember the areas add(cannot have negative area)
    thank you
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