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Math Help - Lines and planes.

  1. #1
    Junior Member
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    Lines and planes.

    it's given the plane determined 2 equations of lines l1 and l2 and it is given point P(3,-4,2) outside the plane find the coordinate of P1 symetric with the plane.

    l_1 : \frac{x-5}{13}=\frac{y-6}{1}=\frac{z+3}{-4}
    l_2 : \frac{x-2}{13}=\frac{y-3}{1}=\frac{z+3}{-4}

    what i did so far is :
    I've found the normal vector of the plane using one vector of the lines and vector M1M2 . M1 is point of line 1 and m2 of l2.
    then i found the equation of the plane using this vector and and a point M1 or M2.
    then i found the equation of the normal line from point P and the normal vector of the plane.
    am i right till here
    Now how to find the coordinates of P1??

    have i to find the length from P to plane, and the point witch the normal line intersect the plane and then using the same distance i should find P1 from point K( where the normal line intersect the plane).



    normal = perpendicular
    Last edited by mr fantastic; April 10th 2010 at 06:45 PM. Reason: Changed post title
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  2. #2
    Junior Member
    Joined
    Oct 2009
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    Now i have an idea
    we must find the vector from point P to the point of intersection of the normal line with the plane K and then this vector add to the coordinates to the point
    K so we found the coordinates P1 ???
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