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Math Help - tricky intergration

  1. #1
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    tricky intergration

    How would I integrate: \int_0^2 \! \dfrac{2x}{x^2+4} \, dx.
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  2. #2
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    Quote Originally Posted by requal View Post
    How would I integrate: \int_0^2 \! \dfrac{2x}{x^2+4} \, dx.
    Hint: the integrand is of the form \frac{u'(x)}{u(x)}...
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