# Math Help - tricky intergration

1. ## tricky intergration

How would I integrate: $\int_0^2 \! \dfrac{2x}{x^2+4} \, dx.$

2. Originally Posted by requal
How would I integrate: $\int_0^2 \! \dfrac{2x}{x^2+4} \, dx.$
Hint: the integrand is of the form $\frac{u'(x)}{u(x)}$...