At the depth T, intensity I = k/2.
So k/2 = 4^-cT*k
2 = 4^cT
ln(2) = cT*ln(4)
Now solve for T.
i have a tricky question here, i hope am putting it in the correct section.
the intensity (I) of a beam of light after passing through a material is given by the formula ( i did it as an attachment so look at it please)
where k is the initial intensity
T is the thickness of the material in cm
c is the absorbtion constant
if the value of c = 0.0101, at what depth will a vertical beam of light be reduced to 50% of its initial intensity.
This is more of a question of what value of T will make will generate 1/2. Or in other words, what value of T we need to cut 4 in half. Since is equivelant to , we can set up a log equation.
So since , then