edit: and are the defining property of exponents. Letting a=-b you get so . Also, so . You can look the others up on wikipedia I think.
My book already tells me the answer to a problem and does it step by step, but I have a question b/w a step.
The original question is here:
Sigma from 1 to infinity of 3^(2k)*5^(1-k)
After that, the book says to simplify it to this:
(9^k)/(5^k-1)
After that, this is where I have my problem. It say to simplify it once more to what I have beloew, only this does not make sense to me. How do you break up a 9^k into a 9 by itself? Furthermore, why is a 9 put into the 1/5? Wouldn't it just be 1/5^k-1 times 9^k? I really do not understand simplifying these types of equations so if anyone could help me with this one or link me to a site that shows how to simplify these things, I would greatly appreciate it. The only rule I know about any number ^k is that anything ^k+1 is the same thing as anything times anything ^k. Is there a list of these rules somewhere dealing with numbers to the power of a variable?
9*(9/5)^k-1