It seems as though it should be arccos(x)*2x, but I copied the problem as it was written in my homework. A hint my teacher said was to set $\displaystyle u = cos^{-1}$ and $\displaystyle dv = dx$, if this helps.
It seems as though it should be arccos(x)*2x, but I copied the problem as it was written in my homework. A hint my teacher said was to set $\displaystyle u = cos^{-1}$ and $\displaystyle dv = dx$, if this helps.
This is what you're looking for
Of course with you having 2x instead of x it is slightly different (your derivative of U will have a 2 on top).