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Math Help - Integration By Parts

  1. #1
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    Post Integration By Parts

    Use integration by parts to evaluate \int{cos^{-1}2xdx}.

    Any help is appreciated!
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  2. #2
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    Is this supposed to be arccos(x)*2x? It appears that you only have one function in your post.
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  3. #3
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    It seems as though it should be arccos(x)*2x, but I copied the problem as it was written in my homework. A hint my teacher said was to set u = cos^{-1} and dv = dx, if this helps.
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  4. #4
    Senior Member AllanCuz's Avatar
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    Quote Originally Posted by live_laugh_luv27 View Post
    It seems as though it should be arccos(x)*2x, but I copied the problem as it was written in my homework. A hint my teacher said was to set u = cos^{-1} and dv = dx, if this helps.
    This is what you're looking for



    Of course with you having 2x instead of x it is slightly different (your derivative of U will have a 2 on top).

    So it will actually become

    xcos^-1 (x) - 2sqrt(1-x^2) + C
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