I could use some help with this problem:

Suppose that f is analytic on a domain D and has a zero of order m at z(subscript 0) in D. Show that:

1.) f' has a zero of order m - 1 at z(subscript 0), and

2.) f^2 has a zero of order 2m at z(subscript 0)

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- April 16th 2007, 08:57 PMspoon737Need some compex analysis help
I could use some help with this problem:

Suppose that f is analytic on a domain D and has a zero of order m at z(subscript 0) in D. Show that:

1.) f' has a zero of order m - 1 at z(subscript 0), and

2.) f^2 has a zero of order 2m at z(subscript 0) - April 16th 2007, 09:02 PMThePerfectHacker
Here is an attempt.

We can write,

f(z) = (z-z_0)^m * g(z) for all z in D.

Then,

f'(z)=m(z-z_0)^{m-1} *g(z) + (z-z_0)^m*g'(z)

f'(z)=(z-z_0)^{m-1}*[mg(z)+(z-z_0)*g'(z)]

We need to show that the second function part does not attain a zero at z_0. Indeed! Substitute and see:

mg(z_0)+0*g'(z_0)=mg(z_0)!=0

Because m!=0 and g(z_0)!=0.

Thus, all the zero's belong to the first factor (z-z_0)^{m-1}.

Which is of order m-1.