Hi all,
I have to find the particular solution to the following, but I am really stumped. I hate to post without showing what I have done, but i really dont know where to start, please advise
dy/dx = x^2 - x + 2 so that y = 0
many thanks
Hi all,
I have to find the particular solution to the following, but I am really stumped. I hate to post without showing what I have done, but i really dont know where to start, please advise
dy/dx = x^2 - x + 2 so that y = 0
many thanks
This one isn't difficult, just integrate both sides...
$\displaystyle \frac{dy}{dx} = x^2 - x + 2$
$\displaystyle y = \int{x^2 - x + 2\,dx}$
$\displaystyle y = \frac{1}{3}x^3 - \frac{1}{2}x^2 + 2x + C$.
What does $\displaystyle x$ equal when $\displaystyle y = 0$?