Results 1 to 2 of 2

Math Help - Particular Solution, Please advise

  1. #1
    Junior Member
    Joined
    Nov 2008
    Posts
    41

    Particular Solution, Please advise

    Hi all,

    I have to find the particular solution to the following, but I am really stumped. I hate to post without showing what I have done, but i really dont know where to start, please advise

    dy/dx = x^2 - x + 2 so that y = 0

    many thanks
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Prove It's Avatar
    Joined
    Aug 2008
    Posts
    11,548
    Thanks
    1418
    This one isn't difficult, just integrate both sides...

    \frac{dy}{dx} = x^2 - x + 2

    y = \int{x^2 - x + 2\,dx}

    y = \frac{1}{3}x^3 - \frac{1}{2}x^2 + 2x + C.


    What does x equal when y = 0?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 1
    Last Post: March 24th 2010, 12:14 AM
  2. Graphing advise please
    Posted in the Algebra Forum
    Replies: 4
    Last Post: January 22nd 2010, 08:42 AM
  3. Can anyone please advise?
    Posted in the Statistics Forum
    Replies: 1
    Last Post: June 28th 2009, 08:16 AM

Search Tags


/mathhelpforum @mathhelpforum