Hi all,

I have to find the particular solution to the following, but I am really stumped. I hate to post without showing what I have done, but i really dont know where to start, please advise :)

dy/dx = x^2 - x + 2 so that y = 0

many thanks :)

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- Apr 9th 2010, 05:44 AMParton-BillParticular Solution, Please advise
Hi all,

I have to find the particular solution to the following, but I am really stumped. I hate to post without showing what I have done, but i really dont know where to start, please advise :)

dy/dx = x^2 - x + 2 so that y = 0

many thanks :) - Apr 9th 2010, 06:43 AMProve It
This one isn't difficult, just integrate both sides...

$\displaystyle \frac{dy}{dx} = x^2 - x + 2$

$\displaystyle y = \int{x^2 - x + 2\,dx}$

$\displaystyle y = \frac{1}{3}x^3 - \frac{1}{2}x^2 + 2x + C$.

What does $\displaystyle x$ equal when $\displaystyle y = 0$?