• April 9th 2010, 05:44 AM
Parton-Bill
Hi all,

I have to find the particular solution to the following, but I am really stumped. I hate to post without showing what I have done, but i really dont know where to start, please advise :)

dy/dx = x^2 - x + 2 so that y = 0

many thanks :)
• April 9th 2010, 06:43 AM
Prove It
This one isn't difficult, just integrate both sides...

$\frac{dy}{dx} = x^2 - x + 2$

$y = \int{x^2 - x + 2\,dx}$

$y = \frac{1}{3}x^3 - \frac{1}{2}x^2 + 2x + C$.

What does $x$ equal when $y = 0$?