Leibniz notation.

**integral** · April 8th 2010, 08:19 PM

How do you use this notation?

If I have
$f(x)=x^3+5x^2+4$

How do you wright this?

**dwsmith** · April 8th 2010, 08:31 PM

How do you write in Leibniz?

$\frac{dy}{dx}$ that means you have to take the derivative though.

**integral** · April 9th 2010, 03:27 AM

Yes, but how do I use it in terms of the equation?

$\frac{dy}{dx}x^3+5x^2+4$

and if I have the notation:

$\frac{d}{dx}$ Or $\frac{d}{dy}$ what does this mean?

?

**coolxal** · April 9th 2010, 03:51 AM

Since $f(x)=x^3+5x^2+4$ , just make y = f(x) so y = $x^3+5x^2+4$ .

dy/dx = f'(x).

dy/dx means derivative of y with respect to x.

d/dx is the derivative with respect to x. If you have $\frac{d}{dx}x^3+5x^2+4$ then you just take the derivative of that.

**CaptainBlack** · April 9th 2010, 04:20 AM

Originally Posted by integral

How do you use this notation?

If I have
$f(x)=x^3+5x^2+4$

How do you wright this?

$\frac{df}{dx}=\frac{d}{dx}(x^3+5x^2+4)=\frac{d}{dx }(x^3)+\frac{d}{dx}(5x^2)+\frac{d}{dx}(4)$

etc

CB

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