I am having trouble with this question: sum 4/(n*(n+2)) from n = 1 to inf - Wolfram|Alpha
(My work is attached)
The correct final answer is: 3.
Any help would be greatly appreciated!
Thanks in advance!
I am having trouble with this question: sum 4/(n*(n+2)) from n = 1 to inf - Wolfram|Alpha
(My work is attached)
The correct final answer is: 3.
Any help would be greatly appreciated!
Thanks in advance!
Write out the first 4 terms and you should see it.
$\displaystyle (\frac{2}{1}-\frac{2}{3})+(\frac{2}{2}-\frac{2}{4})+(\frac{2}{3}-\frac{2}{5})+...+(\frac{2}{n}-\frac{2}{n+2})$
You are left with: $\displaystyle 2+1+\lim_{n\rightarrow \inf }(\frac{2}{n}-\frac{2}{n+2})$