Let y = ln(5x-2) a) Find dy b) Estimate dy for x = 2 and dx = .003. Confused as to what to do, could anyone help?
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Originally Posted by Murphie Let y = ln(5x-2) a) Find dy b) Estimate dy for x = 2 and dx = .003. Confused as to what to do, could anyone help? $\displaystyle dy=y'\,dx$
Originally Posted by Murphie Let y = ln(5x-2) a) Find dy b) Estimate dy for x = 2 and dx = .003. Confused as to what to do, could anyone help? $\displaystyle \frac{dy}{dx} = \frac{d}{dx} log(5x-2) = \frac{1}{5x-2}$ Therefore, $\displaystyle dy = \frac{dx}{5x-2}$ now calculate!
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