Results 1 to 2 of 2

Math Help - limits

  1. #1
    Super Member
    Joined
    Aug 2009
    Posts
    639

    limits

    find the limits of

    (1+2+3+...+n) /n^2
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor undefined's Avatar
    Joined
    Mar 2010
    From
    Chicago
    Posts
    2,340
    Awards
    1
    Quote Originally Posted by alexandrabel90 View Post
    find the limits of

    (1+2+3+...+n) /n^2
    1+2+3+...+n = n(n+1)/2

    (1+2+3+...+n) /n^2 = n(n+1)/(2n^2) = (n^2+n)/(2n^2) = 1/2 + 1/(2n)

    as n goes to infinity, the value of (1+2+3+...+n) /n^2 goes to 1/2.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Limits
    Posted in the Differential Geometry Forum
    Replies: 6
    Last Post: February 10th 2010, 11:24 AM
  2. Using limits to find other limits
    Posted in the Calculus Forum
    Replies: 7
    Last Post: September 18th 2009, 05:34 PM
  3. Function limits and sequence limits
    Posted in the Differential Geometry Forum
    Replies: 0
    Last Post: April 26th 2009, 01:45 PM
  4. Limits
    Posted in the Calculus Forum
    Replies: 5
    Last Post: September 21st 2008, 10:52 PM
  5. [SOLVED] [SOLVED] Limits. LIMITS!
    Posted in the Calculus Forum
    Replies: 1
    Last Post: February 25th 2008, 10:41 PM

Search Tags


/mathhelpforum @mathhelpforum