Results 1 to 2 of 2

Math Help - Reference Triangle for Inverse Trig Functions

  1. #1
    Member
    Joined
    Dec 2009
    Posts
    96

    Reference Triangle for Inverse Trig Functions

    I am not understanding how to do these problems

    I have to do this for

    a) sec^-1 (- sqroot 2)

    b) sec^-1 (2/sq root3)

    c) sec^-1 (-2)

    Can someone please explain to me what to do and how to figure these problems out. Thanks!!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Mar 2010
    From
    Florida
    Posts
    3,093
    Thanks
    5
    Quote Originally Posted by KarlosK View Post
    I am not understanding how to do these problems

    I have to do this for

    a) sec^-1 (- sqroot 2)

    b) sec^-1 (2/sq root3)

    c) sec^-1 (-2)

    Can someone please explain to me what to do and how to figure these problems out. Thanks!!
    a) is just \cos -\sqrt{2}

    b and c are just the cos of the term since \sec =\frac{1}{\cos }

    Therefore, the inverse is just cosine
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Trig functions (angles of a triangle)
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: April 20th 2010, 03:08 AM
  2. Reference Triangles for Inverse Trig Functions
    Posted in the Calculus Forum
    Replies: 3
    Last Post: April 7th 2010, 09:15 AM
  3. Replies: 2
    Last Post: December 9th 2009, 06:09 AM
  4. Reference Triangle for csc(-150degrees)
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: March 9th 2009, 08:14 AM
  5. Inverse Trig Functions and Advance Trig
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: September 24th 2008, 04:13 PM

Search Tags


/mathhelpforum @mathhelpforum