I am not understanding how to do these problems

I have to do this for

a) sec^-1 (- sqroot 2)

b) sec^-1 (2/sq root3)

c) sec^-1 (-2)

Can someone please explain to me what to do and how to figure these problems out. Thanks!!

Printable View

- April 7th 2010, 04:53 PMKarlosKReference Triangle for Inverse Trig Functions
I am not understanding how to do these problems

I have to do this for

a) sec^-1 (- sqroot 2)

b) sec^-1 (2/sq root3)

c) sec^-1 (-2)

Can someone please explain to me what to do and how to figure these problems out. Thanks!! - April 7th 2010, 05:01 PMdwsmith