Can anyone help me on this? I'm trying to find the sum of
$\displaystyle \sum_1^\infty \frac{k}{3^{2k}}$ using power series.
This looks like a geometric sequence to me, but I can't get it in a form that lets me use a power series... any help?
Can anyone help me on this? I'm trying to find the sum of
$\displaystyle \sum_1^\infty \frac{k}{3^{2k}}$ using power series.
This looks like a geometric sequence to me, but I can't get it in a form that lets me use a power series... any help?
$\displaystyle \sum\limits_{k = 1}^\infty {x^k } = \frac{x}{{1 - x}}$
Differenate to get $\displaystyle \sum\limits_{k = 1}^\infty {kx^{k-1} } = \frac{1}{{(1 - x)^2}}$
Multiply by x $\displaystyle \sum\limits_{k = 1}^\infty {kx^{k} } = \frac{x}{{(1 - x)^2}}$.
In your problem let $\displaystyle x=\frac{1}{9}$.