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**Schdero** The antiderivative of the following functions are sought:

1)(x)^1/2. The solution is, in my booklet, 1/2(x)^1/2

But if you use the quotient rule ( f(x)/g(x)' => f'(x)g(x)-f(x)g'(x)/ (g(x))^2)

you get 1/-4x(x)^1/2. Where's the problem? I know, that if you consider 1/(x)^1/2 as x^-1/2 it works out, i just dont see the mistake with applying the quotient rule

2) 2(x^3)^1/2 Here I'm clueless, how do you find the antiderivative at this example?

3) 3sin(x). to me the solution is 3(-cos(x)). In my booklet the solution is 3(cos(x)), but isn't the derivative of cos -> -sinus?

Thanks for you help

Schdero