curl(ФA) at the point (1,1,1)

where A is a vector=(2xz^2)i-(yz)j+(3xz^3)k

and Ф=(x^2)yz

i first multiplied each component of A by (x^2)yz

i then did del cross the vector i got after multiplying A by the scalar to figure out the curl

i came up with (3x^3*z^4+2x^2*y^2*z)i+(9x^2*y*z^4-3x^3*y*z^2)j+(-2y^2*z^2*x-x^3*z^3)k

i then plugged in the point (1,1,1) to the equation for the curl vector and i got 5i+6j-3k but the answer in the book was 5i-3j-4k

am i on the right track here?