I tried doing integration by parts, but I end up getting the wrong answer, help?
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Let $\displaystyle u=x\implies du=dx $ and $\displaystyle dv=f(x)dx\implies v=\int f(x)dx $. So we get $\displaystyle \int xf(x)dx = x\int f(x)dx -\iint f(x)dx dx$. Is this the answer you're looking for?
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