I tried doing integration by parts, but I end up getting the wrong answer, help?

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- Apr 6th 2010, 04:10 PMmaximadeIntegral of xf(x)dx
I tried doing integration by parts, but I end up getting the wrong answer, help?

- Apr 6th 2010, 04:58 PMchiph588@
Let $\displaystyle u=x\implies du=dx $ and $\displaystyle dv=f(x)dx\implies v=\int f(x)dx $.

So we get $\displaystyle \int xf(x)dx = x\int f(x)dx -\iint f(x)dx dx$.

Is this the answer you're looking for?