This is the problem:
Find the relative extrema(if any) and the absolute extrema of the function y=xln(x+3) on the closed interval [0,3].
First you find y' right? I got y'=(x)/(x+3)+log(x+3)
What do i do now?
This is the problem:
Find the relative extrema(if any) and the absolute extrema of the function y=xln(x+3) on the closed interval [0,3].
First you find y' right? I got y'=(x)/(x+3)+log(x+3)
What do i do now?
note that y' > 0 for all x in [0,3] ... what's that tell you?