Show that the tangent to the curve y=(x^2 +x -2)^2 +3 at the point where x=1 is also tangent to the curve at another point.

So far this is what I did:

Subbed in 1 to the oringinal curve to find out that the point is (1,3)

Than I derived it to 4x^3 +6x^2 -6x -4 and when I subbed in 1 into the derivative I got 0.

Than I found out the equation of the line which is y=3, but i'm completely lost on what to do from there