I have a problem which says Y= 3^log(base2)t I set it up as ln y = log(base2)t (ln 3) I am not sure what to do after this step!
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Originally Posted by KarlosK I have a problem which says Y= 3^log(base2)t I set it up as ln y = log(base2)t (ln 3) I am not sure what to do after this step! Use the identity $\displaystyle \log_a x = \frac{\ln x}{\ln a}$.
Originally Posted by KarlosK I have a problem which says Y= 3^log(base2)t I set it up as ln y = log(base2)t (ln 3) I am not sure what to do after this step! $\displaystyle \ln y = \log_2 (t) \cdot \ln(3)$ You can differentiate implictly given that $\displaystyle \frac{d}{dx} \ln (y) = \frac{1}{y} \cdot \frac{dy}{dx} $ You will also need to use the change of base rule on $\displaystyle \log_2 (t)$
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